Derivation→
Let us consider,
The length of the conductor = $l$
The cross-section area of the conductor = $A$
The potential difference across the conductor = $V$
The drift velocity of an electron in conductor = $v_{d}$
Now from the equation of the mobility of electron i.e.
$v_{d}= \mu E$
$v_{d}= \left( \frac{e\tau}{m} \right) E \qquad \left(\because \tau = \frac{e\tau}{m} \right)$
$v_{d}= \left( \frac{e\tau}{m} \right) \frac{V}{l}\qquad (1) \qquad \left(\because E = \frac{V}{l} \right)$
Now from the equation of drift velocity and electric current
$i=neAv_{d}$
Now substitute the value of $v_{d}$ from equation $(1)$ to above equation
$i=neA\left( \frac{e\tau}{m} \right) \frac{V}{l}$
$i=\left( \frac{ne^{2}A\tau}{ml} \right)V$
$\frac{V}{i}=\left( \frac{ml}{ne^{2}A\tau} \right)$
$\frac{V}{i}=R$
Where $R = \frac{ml}{ne^{2}A\tau} $ is known as electrical resistance of the conductor.
Thus
This is Ohm's Law.